duhu
Member
EDITED- Washington can no longer finish higher than 6th or lower than 9th. No longer applicable for previous six way tie for third.
Tiebreaker scenario:
Current standings:
Arizona: 15-2
UCLA: 12-5
Arizona St: 10-7
Colorado: 10-7
Oregon: 9-8
Utah: 9-8
Stanford: 9-8
Cal: 9-8
Washington: 8-9
Oregon State: 7-10
USC: 2-15
Wazzu: 2-15
First, some basic stuff:
USC and Washington State are locked into the 11/12 seeds.
Oregon State is locked into the 10 seed.
Arizona is locked into the 1 seed.
UCLA is locked into the 2 seed.
Seeds #3 to #8 is where it gets mushy. It is possible for a FIVE WAY TIE for third place. ASU, FORD/UTAH, CAL, OREGON, COLORADO could all finish 10-8 in the conference, tied for third place. What is good for Colorado is that they would hold the tiebreaker over most of those schools. I will start with Colorado's pac-12 tourney seed possibilities and probabilities.
A #3 seed is only possible with a win @Cal and an Arizona State loss @Oregon State.
A #4 seed is guaranteed with a win @Cal and an Arizona State win @Oregon State. Even with a loss, a #4 seed is possible, depending on who else is tied with the Buffs.
A #5 seed is possible with a loss @Cal and a Utah loss @ Stanford. Arizona State gets the #3 seed, Cal gets the #4 seed. There are other scenarios as well, depending on who is tied with who, but this is the most basic case.
A #6 seed is possible with a Colorado loss @ Cal, an ASU win @Oregon State, a Utah win @Stanford and an Oregon loss vs Arizona. Arizona State gets the #3 seed, Utah would get the #4 seed and Cal would get the #5 seed. It is also possible under other scenarios, such as one of the six way tie possibilities, mentioned below.
I do not believe a #7 seed or worse is possible. There's a lot of of tiebreaking possibilities so I may have messed up somewhere.
Here's an in-depth look at all the PAC-12 teams from #3 to #8.
The FIVE way tie possibility
Occurs if:
ASU loses @Oregon state
Oregon wins vs Arizona
Colorado loses @ Cal
Winner of Stanford/Utah
For the first tiebreaker in the case of more than two teams, it's best record against the other teams that are tied with you (ie better winning percentage). It's mostly dependent on the winner of Stanford/Utah, but here's how it'd go:
If Stanford wins:
#3 Arizona St: 5-3
#4 Colorado: 3-2
#5 Cal: 3-3 (tiebreaker- better record vs Zona)
#6 Stanford: 3-3
#7 Oregon: 1-4
If Utah wins:
#3 Arizona St: 5-3
#4 Utah: 3-3 (tiebreaker- better record vs UCLA)
#5 Colorado: 3-3
#6 Cal: 2-3 (tiebreaker- head to head over Oregon)
#7 Oregon: 2-3
Thus, Stanford winning over Utah is far more beneficial for Colorado.
Anyway, there are a load of tiebreaking possibilities in this conference this year. Really just depends on who Colorado is tied with. Colorado holds every tiebreaker I can think of over Oregon, Stanford and Washington. Getting a higher seed over Arizona State and Utah is where it could get dicey, depending on who/how many teams are also tied with Colorado. Cal would hold every tiebreaker imaginable over Colorado if Rado were to lose @Cal.
In any case, even with a loss @Cal, the #4 or #5 seed are, statistically, the most likely. Overall, the #4 is slightly more likely than the #5.
Tiebreaker scenario:
Current standings:
Arizona: 15-2
UCLA: 12-5
Arizona St: 10-7
Colorado: 10-7
Oregon: 9-8
Utah: 9-8
Stanford: 9-8
Cal: 9-8
Washington: 8-9
Oregon State: 7-10
USC: 2-15
Wazzu: 2-15
First, some basic stuff:
USC and Washington State are locked into the 11/12 seeds.
Oregon State is locked into the 10 seed.
Arizona is locked into the 1 seed.
UCLA is locked into the 2 seed.
Seeds #3 to #8 is where it gets mushy. It is possible for a FIVE WAY TIE for third place. ASU, FORD/UTAH, CAL, OREGON, COLORADO could all finish 10-8 in the conference, tied for third place. What is good for Colorado is that they would hold the tiebreaker over most of those schools. I will start with Colorado's pac-12 tourney seed possibilities and probabilities.
A #3 seed is only possible with a win @Cal and an Arizona State loss @Oregon State.
A #4 seed is guaranteed with a win @Cal and an Arizona State win @Oregon State. Even with a loss, a #4 seed is possible, depending on who else is tied with the Buffs.
A #5 seed is possible with a loss @Cal and a Utah loss @ Stanford. Arizona State gets the #3 seed, Cal gets the #4 seed. There are other scenarios as well, depending on who is tied with who, but this is the most basic case.
A #6 seed is possible with a Colorado loss @ Cal, an ASU win @Oregon State, a Utah win @Stanford and an Oregon loss vs Arizona. Arizona State gets the #3 seed, Utah would get the #4 seed and Cal would get the #5 seed. It is also possible under other scenarios, such as one of the six way tie possibilities, mentioned below.
I do not believe a #7 seed or worse is possible. There's a lot of of tiebreaking possibilities so I may have messed up somewhere.
Here's an in-depth look at all the PAC-12 teams from #3 to #8.
The FIVE way tie possibility
Occurs if:
ASU loses @Oregon state
Oregon wins vs Arizona
Colorado loses @ Cal
Winner of Stanford/Utah
For the first tiebreaker in the case of more than two teams, it's best record against the other teams that are tied with you (ie better winning percentage). It's mostly dependent on the winner of Stanford/Utah, but here's how it'd go:
If Stanford wins:
#3 Arizona St: 5-3
#4 Colorado: 3-2
#5 Cal: 3-3 (tiebreaker- better record vs Zona)
#6 Stanford: 3-3
#7 Oregon: 1-4
If Utah wins:
#3 Arizona St: 5-3
#4 Utah: 3-3 (tiebreaker- better record vs UCLA)
#5 Colorado: 3-3
#6 Cal: 2-3 (tiebreaker- head to head over Oregon)
#7 Oregon: 2-3
Thus, Stanford winning over Utah is far more beneficial for Colorado.
Anyway, there are a load of tiebreaking possibilities in this conference this year. Really just depends on who Colorado is tied with. Colorado holds every tiebreaker I can think of over Oregon, Stanford and Washington. Getting a higher seed over Arizona State and Utah is where it could get dicey, depending on who/how many teams are also tied with Colorado. Cal would hold every tiebreaker imaginable over Colorado if Rado were to lose @Cal.
In any case, even with a loss @Cal, the #4 or #5 seed are, statistically, the most likely. Overall, the #4 is slightly more likely than the #5.
Last edited: